2[3-2(x+4)]=3(4-x)

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Solution for 2[3-2(x+4)]=3(4-x) equation:


Simplifying
2[3 + -2(x + 4)] = 3(4 + -1x)

Reorder the terms:
2[3 + -2(4 + x)] = 3(4 + -1x)
2[3 + (4 * -2 + x * -2)] = 3(4 + -1x)
2[3 + (-8 + -2x)] = 3(4 + -1x)

Combine like terms: 3 + -8 = -5
2[-5 + -2x] = 3(4 + -1x)
[-5 * 2 + -2x * 2] = 3(4 + -1x)
[-10 + -4x] = 3(4 + -1x)
-10 + -4x = (4 * 3 + -1x * 3)
-10 + -4x = (12 + -3x)

Solving
-10 + -4x = 12 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
-10 + -4x + 3x = 12 + -3x + 3x

Combine like terms: -4x + 3x = -1x
-10 + -1x = 12 + -3x + 3x

Combine like terms: -3x + 3x = 0
-10 + -1x = 12 + 0
-10 + -1x = 12

Add '10' to each side of the equation.
-10 + 10 + -1x = 12 + 10

Combine like terms: -10 + 10 = 0
0 + -1x = 12 + 10
-1x = 12 + 10

Combine like terms: 12 + 10 = 22
-1x = 22

Divide each side by '-1'.
x = -22

Simplifying
x = -22

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